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	<title>Comments on: What&#8217;s Your Erdos Number?</title>
	<link>http://windowsil.org/2008/01/20/whats-your-erdos-number/</link>
	<description>Your window into the Wireless Systems Innovation Laboratory</description>
	<pubDate>Sun, 27 May 2012 13:11:30 +0000</pubDate>
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	<item>
		<title>by: Ali Y. Panah</title>
		<link>http://windowsil.org/2008/01/20/whats-your-erdos-number/#comment-29518</link>
		<pubDate>Mon, 04 Feb 2008 09:29:43 +0000</pubDate>
		<guid>http://windowsil.org/2008/01/20/whats-your-erdos-number/#comment-29518</guid>
					<description>mine is still infinity i guess</description>
		<content:encoded><![CDATA[<p>mine is still infinity i guess
</p>
]]></content:encoded>
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		<title>by: Bob Daniels</title>
		<link>http://windowsil.org/2008/01/20/whats-your-erdos-number/#comment-28597</link>
		<pubDate>Mon, 28 Jan 2008 01:09:05 +0000</pubDate>
		<guid>http://windowsil.org/2008/01/20/whats-your-erdos-number/#comment-28597</guid>
					<description>What's your Heath number?  Mine's 1.</description>
		<content:encoded><![CDATA[<p>What&#8217;s your Heath number?  Mine&#8217;s 1.
</p>
]]></content:encoded>
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	<item>
		<title>by: Robert Heath</title>
		<link>http://windowsil.org/2008/01/20/whats-your-erdos-number/#comment-28140</link>
		<pubDate>Tue, 22 Jan 2008 17:40:44 +0000</pubDate>
		<guid>http://windowsil.org/2008/01/20/whats-your-erdos-number/#comment-28140</guid>
					<description>A little more investigation reveals that my Erdos number is 4 thus all my collaborators have an erdos number of at most 5. Here is one possible chain of authorship through Helmut\'s advisor:

4 Robert W. Heath Jr.
3 Helmut Bölcskei
2 Augustus J. E. M. Janssen
1 Jacobus Hendricus van Lint
0 Paul Erdös</description>
		<content:encoded><![CDATA[<p>A little more investigation reveals that my Erdos number is 4 thus all my collaborators have an erdos number of at most 5. Here is one possible chain of authorship through Helmut\&#8217;s advisor:</p>
<p>4 Robert W. Heath Jr.<br />
3 Helmut Bölcskei<br />
2 Augustus J. E. M. Janssen<br />
1 Jacobus Hendricus van Lint<br />
0 Paul Erdös
</p>
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